# Line slope calculator 3x+y=33

**Straight line given by points A[9; 6] and B[10; 3]**

## Calculation:

**Slope-intercept form of line:**y = -3x+33

**Canonical form of the line equation:**3x+y-33 = 0

**Parametric form of the line equation:**

x = t+9

y = -3t+6 ; t ∈ R

**Slope:**m = -3

**Slope angle of line: φ =**-71°33'54″ = -1.249 rad

**X intercept:**x

_{0}= 11

**Y intercept:**y

_{0}= q = 33

**Distance line from the origin:**d

_{0}= 10.4355

**The length of the segment AB: |AB| =**3.1623

**Vector: AB =**(1; -3)

**Normal vector: n =**(3; 1)

**Midpoint of the segment AB: M =**[9.5; 4.5]

**Perpendicular Bisector equation:**x-3y+4 = 0

**Vector OA = (9; 6) ; |OA| = 10.8167**

**Vector OB = (10; 3) ; |OB| = 10.4403**

**Scalar product OA .OB = 108**

**Angle ∠ AOB = 16°59'27″ = 0.2965 rad**